A body of mass 5 kg, initially at rest, moves under the action of an applied force of 15N on a horizontal surface with a coefficient of friction 0.25. Calculate (a) Work done by the force (b) Work done by friction (c ) Work done by net force (d) Change in kinetic energy in 5s.

A body of mass 5 kg, initially at rest, moves under the action of an a

1.	A body of mass 5 kg, initially at rest, moves under the action of an applied force of 15N on a horizontal surface with a coefficient of friction 0.25. Calculate (a) Work done by the force (b) Work done by friction (c ) Work done by net force (d) Change in kinetic energy in 5s.
Answer» Solution :GIVEN, `m=5kg,t=5s`, FORCE of FRICTION `f=mumg=0.25xx5xx9.8=12.25N` Net force on the body `=15-12.25=2.75N` ACCELERATION of body = `(2.75)/(5)=0.55ms^(-2)`