1.

A body of mass 5 kg is lifted vertically at a constant velocity of 12m. calculate a) the force applied b) work done in lifting the body c) what happens to the work performed?

Answer»

to Newton's 2nd law of MOTION, F=ma.therefore, force= 5x 9.8 ( 9.8 is the ACCELERATION due to GRAVITY) f = 49NB. W= FXS (s is the displacement) w= kinetic energy.therefore, k.e. = 1/2mv² k.e. is equal to 1/2x 5x 12x12= 360 joule. therefore work done is 3.6 x 10² joule.



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