A body of mass 500 g is at rest on a frictionless surface. Calculate t

1.	A body of mass 500 g is at rest on a frictionless surface. Calculate the distance travelled by it in 10 second when acted upon by a force of 10-2 N.
Answer» Force = 10^-2 N = 0.01 N initial velocity, u = 0 mass, m = 500 g = 0.5 kg distance travelled, s =? time, t = 10 sec Force = mass × acceleration acceleration, a =\(\frac{force}{mass}\) = \(\frac{0.01}{0.5}\)= 0.02 m/s² Using the equation, s = ut + \(\frac{1}{2}\) at² =0×10+\(\frac{1}{2}\)×0.02×10²= 1

A body of mass 500 g is at rest on a frictionless surface. Calculate the distance travelled by it in 10 second when acted upon by a force of 10-2 N.

Answer»

Force = 10^-2 N = 0.01 N initial velocity, u = 0

mass, m = 500 g = 0.5 kg distance travelled, s =? time, t = 10 sec

Force = mass × acceleration

acceleration, a =\(\frac{force}{mass}\) = \(\frac{0.01}{0.5}\)= 0.02 m/s²

Using the equation, s = ut + \(\frac{1}{2}\) at²

=0×10+\(\frac{1}{2}\)×0.02×10²= 1