A body of mass 5kg is thrown up vertically with a kinetic energy of 1000J. If acceleration due to gravity is 10ms^(-2), find the height at which the kinetic energy becomes half of the original value.

A body of mass 5kg is thrown up vertically with a kinetic energy of 10

1.	A body of mass 5kg is thrown up vertically with a kinetic energy of 1000J. If acceleration due to gravity is 10ms^(-2), find the height at which the kinetic energy becomes half of the original value.
Answer» <html><body><p>10m <br/><a href="https://interviewquestions.tuteehub.com/tag/20m-293046" style="font-weight:bold;" target="_blank" title="Click to know more about 20M">20M</a> <br/>50 m <br/>100 m </p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> : Half KE is converted into <a href="https://interviewquestions.tuteehub.com/tag/potential-1161228" style="font-weight:bold;" target="_blank" title="Click to know more about POTENTIAL">POTENTIAL</a> energy . <br/> then `PE =1/2 KE` <br/> ` <a href="https://interviewquestions.tuteehub.com/tag/mgh-1095458" style="font-weight:bold;" target="_blank" title="Click to know more about MGH">MGH</a> = 1000/2 = 500` <br/> ` <a href="https://interviewquestions.tuteehub.com/tag/h-1014193" style="font-weight:bold;" target="_blank" title="Click to know more about H">H</a> = (500)/(mg) = (500)/(5 xx 10) = 10m `</body></html>