A body of mass 5kg is thrown up vertically with a kinetic energy of 1000J. If acceleration due to gravity is 10ms^(-2), find the height at which the kinetic energy becomes half of the original value.

A body of mass 5kg is thrown up vertically with a kinetic energy of 10

1.	A body of mass 5kg is thrown up vertically with a kinetic energy of 1000J. If acceleration due to gravity is 10ms^(-2), find the height at which the kinetic energy becomes half of the original value.
Answer» 10m 20M 50 m 100 m SOLUTION : Half KE is converted into POTENTIAL energy . then `PE =1/2 KE` ` MGH = 1000/2 = 500` ` H = (500)/(mg) = (500)/(5 xx 10) = 10m `