A body of mass `8kg` is moved by a force `F = (3x)N`, where x is the disatance covered Initial position is `x =2m` and final position is `x =10m` If initially the body is at rest find the final speed .

A body of mass `8kg` is moved by a force `F = (3x)N`, where x is the d

1.	A body of mass `8kg` is moved by a force `F = (3x)N`, where x is the disatance covered Initial position is `x =2m` and final position is `x =10m` If initially the body is at rest find the final speed .
Answer» `F =ma rArr F =m (dv)/(dt) rArr 3 x = m (dv)/(dx) (dx)/(dt)` `3x = 8 (dv)/(dx) v rArr 3xdx = 8vdv` `3int_(2)^(10)xdx=int_(0)^(v)vdxrArr3[x^(2)/2]_(2)^(10) = [v^(2)/(2)]_(0)^(v)` `3[100-4] = 8 v^(2) rArr v^(2) = (3 xx 96)/(8) = 36 rArr v = 6 ms^(-1)`

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A body of mass `8kg` is moved by a force `F = (3x)N`, where x is the disatance covered Initial position is `x =2m` and final position is `x =10m` If initially the body is at rest find the final speed .

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