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A body of mass 8kg lies on a rough horizontal table. It is observed that a certain horizontal force gives the body an acceleration of the body is `16ms^(-2)` . The coefficient of friction is.A. `0.2`B. `0.3`C. `0.4`D. `0.8` |
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Answer» Correct Answer - D `F-f=8xx4=32 `(i) `2F-f=128` (ii) `"Multiplying"` (i) by (ii), we get `2F-2f=64` (iii) Also, (ii)-(iii) gives `f=128-64=64N` `mumg= muxx8xx10=64` or `mu=(64)/(80)=(80)/(100)=0.8` . |
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