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A body of mass `m_(1) = 4kg moves at `5 hat(i) ms^(-1)` and another body of mass `m_(2) = 2kg` moves at `10hat(i)ms^(-1)`. The kinetic energy of center of mass isA. `200/3J`B. `500/3J`C. `400/3J`D. `800/3J` |
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Answer» Correct Answer - C `v_(CM) = (m_(1)(dr_(1))/(dt)+m_(2)(dr_(2))/dt)/(m_(1) + m_(2)) = (4 xx 5hat(i) + 2 xx 10hat(j))/(4+2)` `v_(CM) = (40hat(i))/6 = 20/3hat(i)` The kinetic energy, `K = 1/2mv^(2) = 1/2xx(4+2) xx(20 xx 20)/(3 xx 3)` `=1/2 x 6 xx (20 xx 20)/(3 xx 3) = 400/3 J` |
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