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A body of mass `m_(1) ` moving with uniform velocity of 40 m/s collides with another mass `m_(2)` at rest and then the two together begin to moe wit h uniform velocity of 30 m/s. the ratio of their masses `(m_(1))/(m_(2))` isA. `1:3`B. `3:1`C. `1:1.33`D. `1: 0.75` |
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Answer» Correct Answer - B (b) Initial momentum of the sytem `=m_(1) xx 40 + m_(2) xx 0 = 40m_(1)` Final momentum of the system. `=m_(1) xx 40 + m_(2) xx 0 = 40m_(1)` Final momentumof the system, `=(m_(1) + m_(2)) xx 30` ltbrlt By law of conservation of momentum, Initial momentum = Final momentum `40m_(1) = ((m_(1) + m_(2))30` `40m_(1) - 30m_(1) = 30m_(2)` `10m_(1) = 30m_(2)` `m_(1)/m_(2) = 3/` |
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