1.

A body of mass `m_(1) ` moving with uniform velocity of 40 m/s collides with another mass `m_(2)` at rest and then the two together begin to moe wit h uniform velocity of 30 m/s. the ratio of their masses `(m_(1))/(m_(2))` isA. `1:3`B. `3:1`C. `1:1.33`D. `1: 0.75`

Answer» Correct Answer - B
(b) Initial momentum of the sytem
`=m_(1) xx 40 + m_(2) xx 0 = 40m_(1)`
Final momentum of the system.
`=m_(1) xx 40 + m_(2) xx 0 = 40m_(1)`
Final momentumof the system,
`=(m_(1) + m_(2)) xx 30` ltbrlt By law of conservation of momentum,
Initial momentum = Final momentum
`40m_(1) = ((m_(1) + m_(2))30`
`40m_(1) - 30m_(1) = 30m_(2)`
`10m_(1) = 30m_(2)`
`m_(1)/m_(2) = 3/`


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