A body of mass .m. and radius .r. rolling on a horizontal floor with velocity .v., rolls up an inclined plane up to vertical height (3V^(2))/(4g). Find the momentu of inertia of body and comment on its shape

A body of mass .m. and radius .r. rolling on a horizontal floor with v

1.	A body of mass .m. and radius .r. rolling on a horizontal floor with velocity .v., rolls up an inclined plane up to vertical height (3V^(2))/(4g). Find the momentu of inertia of body and comment on its shape
Answer» Solution :The total KE of the body `K=K_(T)+K_(R )=(1)/(2)mv^(2)[1+(I)/(mr^(2))]` When rolls up an inclined plane of HEIGHT `h = (3V^(2))/(4g)`its KE is covereted into PE. So `(1)/(2)mv^(2)[1+(I)/(mr^(2))]=mg((3v^(2))/(4g))` on SIMPLIFICATION `I=(mr^(2))/(2)` HENCE the body is either a disc or cylinder.