A body of mass .m. and radius .r. rolling on a horizontal floor with velocity .y., rolls up an inclined plane up to vertical height (3V^2)/(4g). Find the moment of inertia of body and comment on its shape

A body of mass .m. and radius .r. rolling on a horizontal floor with v

1.	A body of mass .m. and radius .r. rolling on a horizontal floor with velocity .y., rolls up an inclined plane up to vertical height (3V^2)/(4g). Find the moment of inertia of body and comment on its shape
Answer» Solution :The TOTAL KE of the body `K=K_(T)+K_(R)=(1)/(2)mv^(2)[1+(I)/(MR^(2))]` When ROLLS up an inclined plane of height `h=(3V^(2))/(4g)` its KE is converted into PE. So `(1)/(2)mv^(2)[1+(I)/(mr^(2))]=mg((3v^(2))/(4g))` on simplification `I=(mr^(2))/(2)` hence the body is either a disc or CYLINDER.