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A body of mass m has an initial speed v is acted by two forces `vec(F)_(1)` and `vec(F)_(2)`. After something work done by `vec(F)_(1)` is `-1/2 mv^(2)` and speed of the body is 2v. Then, the work done by `vec(F)_(2)` isA. `3/2 mv^(2)`B. `mv^(2)`C. zeroD. `2mv^(2)` |
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Answer» Correct Answer - D `W_(1)+W_(2)=1/2 m(2v)^(2)-(v)^(2)` `-1/2 mv_(2)+W_(2)=3/2 mv^(2)` `W_(2)=2mv^(2)` |
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