A body of mass 'm' kg starts falling from a point 2R above the Earth's surface. What is its K.E. When it has fallen to a point 'R' above the Earth's surface.

A body of mass 'm' kg starts falling from a point 2R above the Earth's

1.	A body of mass 'm' kg starts falling from a point 2R above the Earth's surface. What is its K.E. When it has fallen to a point 'R' above the Earth's surface.
Answer» Solution :Potentialenergy` U =(-GMM)/r= (GMm)/(R+h)` `U_("intial") = -(GMm)/randU_("final") = - (GMm)/(2R)` LOSS of P.E = gain in K.E = `(GMm)/(2R) - (GMm)/(3R) = (GMm)/(6R)` ` :. K.E = (GMm)/(6R)`