A body of mass m moving with a uniform velocity of 40 m s^(-1) collides with another body of mass m, at rest and then the two together begin to move with a uniform velocity of 30 m s^(-1) The ratio of their masses ((m_1)/(m_2)) is

A body of mass m moving with a uniform velocity of 40 m s^(-1) collide

1.	A body of mass m moving with a uniform velocity of 40 m s^(-1) collides with another body of mass m, at rest and then the two together begin to move with a uniform velocity of 30 m s^(-1) The ratio of their masses ((m_1)/(m_2)) is
Answer» 0.75 0.33 3 1.33 Solution :Applying the law of CONSERVATION of linear momentum , we get `m_1 XX 40 + m_2 xx 0 = (m_1 + m_2) 30` `:. 40/30 = (m_1 + m_3)/(m_1) = 1 + (m_2)/(m_1)` `:. (m_2)/(m_1) = 40/30 - 1 = 10/30 = 1/3 "or" (m_1)/(m_2) = 3/1`.