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A body of mass m tied to a spring performs SHM with period 2 seconds. If the mass is increased by 3m, what will be the period of SHM ? |
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Answer» T = 2\(\pi\) \(\sqrt{\frac mk}\) \(\therefore\) \(\frac{T_2}{T_1}\) = \(\sqrt{\frac {m_2}{m_1}}\) = \(\sqrt{\frac {m+3m}{m}}\) = √4 = 2 ∴ T2 = 2T1 = 2 × 2 = 4 seconds gives the required period of SHM. |
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