A body of mass ‘M’moving with velocity 'V'explodes into two equal parts. If one comes to rest and the other body moves with the velocity 'v' what is the value of 'v'?

A body of mass ‘M’moving with velocity 'V'explodes into two equal

1.	A body of mass ‘M’moving with velocity 'V'explodes into two equal parts. If one comes to rest and the other body moves with the velocity 'v' what is the value of 'v'?
Answer» `V` `(V)/(sqrt2)` `4V` `2V` SOLUTION :Before explosion , the total momentum of the sysmtem= MV After explosion , the total momentum of the system` = M/2 xx 0+ M/2 xx v = (Mv)/(2)` PRINCIPLE of momentum conservation, before= after ` MV = (Mv)/(2) RARR v = 2V