1.

A body performing SHM about its mean position with period 24 s, after 4 s its velocity is `pi m//s`, then its path will beA. 48 mB. 24 mC. 52 mD. 12 m

Answer» Correct Answer - B
`T=24s`
`v=Aomegacosomegat`
`pi=Axx(2pi)/(T)xxcos((2pi)/(24)xx4)`
`1=Axx(2)/(24)xxcos.(pi)/(3)`
`12=(A)/(2)`
`therefore A=24m`


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