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A body performing SHM about its mean position with period 24 s, after 4 s its velocity is `pi m//s`, then its path will beA. 48 mB. 24 mC. 52 mD. 12 m |
Answer» Correct Answer - B `T=24s` `v=Aomegacosomegat` `pi=Axx(2pi)/(T)xxcos((2pi)/(24)xx4)` `1=Axx(2)/(24)xxcos.(pi)/(3)` `12=(A)/(2)` `therefore A=24m` |
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