InterviewSolution
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InterviewSolution
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A body projected from the surface of the earth attains a height equal to the radius of the earth. The velocity with which the body was projected isA. `sqrt((2GM)/( R))`B. `sqrt((GM)/( R))`C. `sqrt((3GM)/( R))`D. `sqrt((5GM)/(4R))` |
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Answer» Correct Answer - B Applying the principle of conservation of energy, `E_("surface of the earth")=E_("at a height h")` equal to R `(1)/(2)mv^(2)-(GMm)/(R )=(1)/(2)m(0)^(2)-(GMm)/(R+R)` [`because` The velocity of the highest point = 0] `therefore (1)/(2)mv^(2)=(GMm)/(R )-(GMm)/(2R)=(GMm)/(2R)` `v^(2)=(GM)/(R )` or `v=sqrt((GM)/(R ))` |
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