A body projected from the top of a tower with a velocity vec(u) = 3hat(i) + 4hat(j) + 5hat(k) ms^(-1). Where hat(i), hat(j) and hat(k) are unit vectors along east, north and vertically upwards respectively. If the height of the tower is 30m, horizontal range of the body on the ground is (g = 10 ms^(-2))

A body projected from the top of a tower with a velocity vec(u) = 3hat

1.	A body projected from the top of a tower with a velocity vec(u) = 3hat(i) + 4hat(j) + 5hat(k) ms^(-1). Where hat(i), hat(j) and hat(k) are unit vectors along east, north and vertically upwards respectively. If the height of the tower is 30m, horizontal range of the body on the ground is (g = 10 ms^(-2))
Answer» 12m 9m 25m 15m Answer :D