A body projected up reaches a point A in its path at the end of 4^(th) second and reaches the ground after 5 seconds from the start. The height of A above the ground is (g=10ms^(2))

A body projected up reaches a point A in its path at the end of 4^(th)

1.	A body projected up reaches a point A in its path at the end of 4^(th) second and reaches the ground after 5 seconds from the start. The height of A above the ground is (g=10ms^(2))
Answer» `19.6m` `30.6m` `11M` `20M` ANSWER :D