A body projected up reaches a point A in its path at the end of 4^(th) second and reaches the ground after 5 seconds from the start. The height of A above the ground is (g=10ms^(2))

A body projected up reaches a point A in its path at the end of 4^(th)

1.	A body projected up reaches a point A in its path at the end of 4^(th) second and reaches the ground after 5 seconds from the start. The height of A above the ground is (g=10ms^(2))
Answer» <html><body><p>`19.6m`<br/>`30.6m`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/11m-268878" style="font-weight:bold;" target="_blank" title="Click to know more about 11M">11M</a>`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/20m-293046" style="font-weight:bold;" target="_blank" title="Click to know more about 20M">20M</a>`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html>