A body projected up reaches a point A in its path at the end of 4th second and reaches the ground after 5 seconds from the start. The height of A above the ground is (g=10m//s^(2))

A body projected up reaches a point A in its path at the end of 4th se

1.	A body projected up reaches a point A in its path at the end of 4th second and reaches the ground after 5 seconds from the start. The height of A above the ground is (g=10m//s^(2))
Answer» 19.6m 30.6m 11m 20m Answer :D