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A body, rpojected horizontally with a speed `u` from the top of a tower of height `h`, reaches the ground at a horizontally distance `R` from the tower. Another body, projected horizontally from the top of a tower of height `4h`, reaches the ground at horizontal distance `2R` from the tower. The initial speed of the second body isA. `u`B. `2u`C. `3u`D. `4u` |
Answer» Correct Answer - A `y = (g x^(2))/(2 u^(2))` `h = (g R^(2))/(2 u^(2)), 4h = (g(2 R)^(2))/(2 u_(1)^(2))` `u_(1) = u` |
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