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| 1. |
A body started to move from rest and with uniform acceleration 1.6m/s^2 Calculate the final velocity and distance travelled by a body in 2 minutes |
| Answer» <html><body><p><strong>Answer:</strong></p><p>Given :</p><p>▪ Initial velocity of <a href="https://interviewquestions.tuteehub.com/tag/body-900196" style="font-weight:bold;" target="_blank" title="Click to know more about BODY">BODY</a>=zero</p><p></p><p>▪ Acceleration of the body=1.6m/s</p><p></p><p>To <a href="https://interviewquestions.tuteehub.com/tag/find-11616" style="font-weight:bold;" target="_blank" title="Click to know more about FIND">FIND</a> :</p><p>▪ Velocity and distance travelled by the body in 2min.</p><p></p><p>Formula used :</p><p>▪ Since, acceleration is constant <a href="https://interviewquestions.tuteehub.com/tag/throughout-7258007" style="font-weight:bold;" target="_blank" title="Click to know more about THROUGHOUT">THROUGHOUT</a> the whole journey, we can apply equations of kinematics directly.</p><p></p><p>▪ <a href="https://interviewquestions.tuteehub.com/tag/first-461760" style="font-weight:bold;" target="_blank" title="Click to know more about FIRST">FIRST</a> equation of kinematics :</p><p></p><p>☞ v = u + at</p><p>▪ Third equation of kinematics :</p><p></p><p>☞ s = ut + (1/2)at^2</p><p>▪ 2min = 120sec</p><p></p><p>Calculation :</p><p>Final velocity</p><p>→ v = u + at</p><p></p><p>→ v = 0 + (1.6)(120)</p><p></p><p>→ v = 192m/s</p><p>Distance travelled</p><p>→ s = ut + (1/2)at^2</p><p></p><p>→ s = 0(120) + [0.5×1.6×(120)^2]</p><p></p><p>→ s = 0.5×1.6×14400</p><p></p><p>→ s = 11520m = 11.52km</p><p><strong>Explanation:</strong></p><p></p></body></html> | |