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A body , starting from rest and moving with constant acceleration , covers 10 m in the first second. Find the distance travelled by it in the next second. |
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Answer» SOLUTION :Using the equation for the DISTANCE TRAVELLED in the `n^(th)` second , `viz,. S_(n)=u+a/2(2n-1)` We have for thefirst second , `10=0+2/2(2xx2-1)=30m. ` Noth: FOLLOWING this procedure it can be SHOWN that the distance travelled in equal time intervals will be in the ratio `1:3:5:7:`.... |
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