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A body starting from rest has an acceleration of `4ms^(-2)` . Calculate distnce travelled by it in 5th second. |
Answer» Given, `u=O, a=4 ms^(-2)` Distance travelled in 5th second `s_(n)=u+(1)/(2)a(2n-1)` `s_(5)=0+(1)/(2)xx4(2xx5-1)=(1)/(2)xx4(9)=(36)/(2)=18 m` |
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