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A body starts from rest and covers a distance of \( 10 m \) in first second. The distance covered by it in 4 seconds will be: 1) \( 80 m \) 2) \( 100 m \) 3) \( 160 m \) 4) \( 200 m \) |
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Answer» u = 0 s = 10 t = 1 \(\therefore \) s = ut + \(\frac12\)a t2 ⇒ 10 = \(\frac12\) x a x 12 ⇒ a = 20 m/sec2 Now, t = 4 a = 20 u = 0 \(\therefore \) s = ut + \(\frac12\)a t2 = 0 + \(\frac12\) x 20 x 16 = 160 m. Correct option is 3) 160 m |
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