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A body starts from rest and moves with constant acceleration. The ratio of distance covered by the body in `nth` second to that covered in `n` second is.A. `2/(n^(2))-1/n`B. `2/(n^(2))+1/n`C. `2/n-1/(n^(2))`D. `2/n+1/(n^(2))` |
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Answer» Correct Answer - C distance covered `n^(th)` second is `(a)/(2)(2n-1)` distance covered in n second `=1/2 an^(2)` this implies ratio `=2/n-1/(n^(2))` |
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