A body starts from rest and moves with uniform acceleration of 5ms^(-2) for 8 seconds. From that time the acceleration ceases. Find the distance covered in 12s starting from rest.

A body starts from rest and moves with uniform acceleration of 5ms^(-2

1.	A body starts from rest and moves with uniform acceleration of 5ms^(-2) for 8 seconds. From that time the acceleration ceases. Find the distance covered in 12s starting from rest.
Answer» <html><body><p></p>Solution :The <a href="https://interviewquestions.tuteehub.com/tag/velocity-1444512" style="font-weight:bold;" target="_blank" title="Click to know more about VELOCITY">VELOCITY</a> after 8 seconds `v=0+5xx8=40m//s` <br/> Distance covered in 8 seconds <br/> `s_(0)=0+(1)/(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)xx5xx64=160n` <br/> After <a href="https://interviewquestions.tuteehub.com/tag/8s-340210" style="font-weight:bold;" target="_blank" title="Click to know more about 8S">8S</a> the body moves with <a href="https://interviewquestions.tuteehub.com/tag/uniform-1437485" style="font-weight:bold;" target="_blank" title="Click to know more about UNIFORM">UNIFORM</a> velocity and distance covered in 4s with uniform velocity is <br/> `S=vt=40xx4=160m` <br/> The distance covered in `12s=160+160=320m`</body></html>