A body starts from rest and moves with uniform acceleration of 5ms^(-2) for 8 seconds. From that time the acceleration ceases. Find the distance covered in 12s starting from rest.

A body starts from rest and moves with uniform acceleration of 5ms^(-2

1.	A body starts from rest and moves with uniform acceleration of 5ms^(-2) for 8 seconds. From that time the acceleration ceases. Find the distance covered in 12s starting from rest.
Answer» Solution :The VELOCITY after 8 seconds `v=0+5xx8=40m//s` Distance covered in 8 seconds `s_(0)=0+(1)/(2)xx5xx64=160n` After 8S the body moves with UNIFORM velocity and distance covered in 4s with uniform velocity is `S=vt=40xx4=160m` The distance covered in `12s=160+160=320m`