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A body starts rolling over a horizontal surface with an initial velocity of `0.5 m//s^(2)`. Due to friction , its velocity decreases at the rate of `0.05 m//s^(2)`. How much time will it take for the body to stop? |
Answer» Correct Answer - `10 s` Here, ` u = 0 = 0.5 m//s^(2) , a = - 0.05 m//s^(2) , v = 0 , t = ?` From `a = ( v - u)/( t) , t = ( v - u)/( a) or t = ( 0 - 0.5)/(-0.05) = 10 s` |
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