A body starts to slide over a horizontal surface with an initial veloc

1.	A body starts to slide over a horizontal surface with an initial velocity of 0.5 m/s. Due to friction, its velocity decreases at the rate 0.105 m/s2 . How much time will it take for the body to stop?
Answer» Using the first equation of motion: v = u + at where: v = final velocity = 0 m/s u = initial velocity = 0.5 m/s a = acceleration = -0.105 m/s² t = time = ?? v = u + at 0 = 0.5 - 0.105 x t0.105 x t = 0.5 t =\(\frac{0.5}{0.105}\) s =4.76 s

A body starts to slide over a horizontal surface with an initial velocity of 0.5 m/s. Due to friction, its velocity decreases at the rate 0.105 m/s2 . How much time will it take for the body to stop?

Answer»

Using the first equation of motion: v = u + at

where: v = final velocity = 0 m/s

u = initial velocity = 0.5 m/s

a = acceleration = -0.105 m/s²

t = time = ??

v = u + at

0 = 0.5 - 0.105 x t0.105 x t = 0.5

t =\(\frac{0.5}{0.105}\) s =4.76 s