A body travelling with a uniform acceleration travels a distance of 10

1.	A body travelling with a uniform acceleration travels a distance of 100m in the first 5 second and 200m in the next 5 second, calculate the initial velocity and acceleration of the body.
Answer» If s₁ and s₂ are the distances travelled by a body in two successive intervals of t seconds, then the acceleration is given by, a = (s2 - s1)t²= (200 - 100)/5² = 100/25 = 4ms^-2 we have, s = ut + 1/2 at² Here, s = s₁ = 100m, a = 4ms^-2, t = 5 s 100 = u × 5 + 1/2 × 4 × 25 OR 5u = 50 ∴ u = 10ms^-1

A body travelling with a uniform acceleration travels a distance of 100m in the first 5 second and 200m in the next 5 second, calculate the initial velocity and acceleration of the body.

Answer»

If s₁ and s₂ are the distances travelled by a body in two successive intervals of t seconds, then the acceleration is given by,

a = (s2 - s1)t²= (200 - 100)/5² = 100/25 = 4ms^-2

we have, s = ut + 1/2 at²

Here, s = s₁ = 100m, a = 4ms^-2, t = 5 s

100 = u × 5 + 1/2 × 4 × 25

OR 5u = 50 ∴ u = 10ms^-1