1.

A body travels 200 can in the first 2seconds and 220 cm in the next 2 seconds.what is the initial velocity of the body?​

Answer»

Explanation:

s=ut+21at2

For case 1.

200=2u+2a

u+a=100....(1)

For case 2. .i.e. next 4 SECONDS, we have distance =420 CM and time =6 s

420=6u+18a

u+3a=70....(2)

SOLVING equation 1 and 2, we GET

u=115 cm/s and a=−15 cm/s2

Now by 

v=u+at

v=115−15×7

v=10 cm/s

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