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A body travels uniformly a distance of (13.8 pm 0.2)m in a time (4.0 pm 0.3)s. Determine velocity of the body within error limits. |
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Answer» Solution :Here `s=(13.8pm0.2)m` and `t=(4.0 pm 0.3)SEC` Expressing it in percentage error, we have, `s=13.8 pm (0.2)/(13.8)xx100%` `=13.8pm 1.4%` and `t=4.0pm (0.3)/(4)xx100%` `=4PM 7.5%` `THEREFORE V=(s)/(t)=(13.8 pm 1.4)/(4pm 7.5)` `=(3.45pm0.18)m//s` |
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