A body undergoes no change in volume. Poisson's ratio is

1.	A body undergoes no change in volume. Poisson's ratio is
Answer» 0.5 0.05 0.25 2.5 Solution :`(Delta V)/(V) = (Delta (pi r^(2) l))/(pi r^(2) l) = (r^(2) Delta l+ 2r l Delta r)/(r^(2) l)` or `(Delta V)/(V) = (Delta l)/(l) + (2 Delta r)/(r )` As `Delta V= 0` (Given), `0 = (Delta l)/(l)(2 Delta r )/(r )` or `(Delta l)/(l) = - (2DELTA r)/(r )` Poisson.s ratio, `sigma = - (Delta r//r)/(Delta l//l) = (Delta r//r)/(2 Delta r//r) = (1)/(2) = 0.5`

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