A body weighing 0.02 kg has a velocity of 0.06 ms^(-1)after one second of start from the mean position. If the time period is 6 s find the K.E., P.E. and the total energy.

A body weighing 0.02 kg has a velocity of 0.06 ms^(-1)after one second

1.	A body weighing 0.02 kg has a velocity of 0.06 ms^(-1)after one second of start from the mean position. If the time period is 6 s find the K.E., P.E. and the total energy.
Answer» Solution :K.E. `= (1//2) mv^2 =3.6 xx10^(-5) JV = aomegacos OMEGAT , 0.06= a (2pi//T) COS (2pi//T) cos (2pi//T) xx1` Solving a = `(0.36//pi)m`