A body weighs 63 N on the surface of the earth. What is the gravitational force on it due to the earth at a height equal to half the radius of the earth ?

A body weighs 63 N on the surface of the earth. What is the gravitatio

1.	A body weighs 63 N on the surface of the earth. What is the gravitational force on it due to the earth at a height equal to half the radius of the earth ?
Answer» Solution :`implies` Here `h = (R_E)/ 2` ACCELERATION DUE to gravity at height h from the surface of earth, `g(h) = g_e/((1+h/R_E)^2)` `= (g_e)/([1+(R_E/2)/(R_E)]^(-2))[:. h=R_E/2]` `=g_e/((1+1/2)^2)` `:. g(h) = 4/9 "ge"` WEIGHT on earth W = mg = 63 N Weight at a height EQUAL to half of radius of theearth `(h =(R_E)/2)` from the surface of earth. `W= mg (h) = 4/9 "mge"` `:. W. = 4/9 (63)[ :. mg_e = 63 N]` `:. W. = 28 N`