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A body when projected vertically up , covers a total distance D, During the time of tis flight t. If there were no gravity , find the distance covered by it during the same time |
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Answer» Solution :The displacement of the body during the time t as it attains the point of projection `RARR S = 0 ` `rArr v_(0)t-1/2"gt"^(2)=0` `rArr t=(2v_(0))/g` DRING the same time t, the body moves in ABSENCE of gravity through a distance `D.=v_(0)t,` because in absence of gravety g=0 `rArr D. =v_(0)((2v_(0))/g)=(2v_(0)^(2))/g` In presence of gravity the total distance COVERED is `=D=2H=2(v_(0)^(2))/(2g)=(v_(0)^(2))/g (1)-:(2)rArr D.=2D` |
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