1.

A body when projected vertically up , covers a total distance D, During the time of tis flight t. If there were no gravity , find the distance covered by it during the same time

Answer»

Solution :The displacement of the body during the time t as it attains the point of projection
`RARR S = 0 `
`rArr v_(0)t-1/2"gt"^(2)=0`
`rArr t=(2v_(0))/g`
DRING the same time t, the body moves in ABSENCE of gravity through a distance
`D.=v_(0)t,` because in absence of gravety g=0
`rArr D. =v_(0)((2v_(0))/g)=(2v_(0)^(2))/g`
In presence of gravity the total distance COVERED is `=D=2H=2(v_(0)^(2))/(2g)=(v_(0)^(2))/g
(1)-:(2)rArr D.=2D`


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