1.

A bodyinitially at rest and sliding along a frictionlss track from a height h (as shown in the figure ) jut completes a vertical circle of diameter AB = D .the height h is equal to ……….

Answer»

`5/4 `D
`3/2` D
`7/5` D
D

Solution :SPEED near the vertical circle A , `v_(A) = sqrt(5gR)` where ,R = radius of circle (from the law of conservation of energy ).
Potential energy is converted into kinetic energy .
`mgh= 1/2 mv_(A)^(2)`
` :. H = ((v_Delta)^(2))/(2G)`
` = (5gR)/(2g)`
` = (5D)/(2xx2)`
` :. h =5/4D `


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