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A Bohr hydrogen atom undergoes a transition n=5rarrn=4 and emits a photon of frequency v. Frequency of circular motion of electron in n = 4 orbit is V_(4). Find the ratio v//v_(4).(54)/(25N), where N is an integer find N |
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Answer» `E_(n)=-(MZ^(2)e^(4))/(8 epsilon_(0)^(2)n^(2)h^(2))` so , `hv=+(mz^(2)e^(4))/(8 epsilon_(0)^(2)h^(2))[(1)/(16)-(1)/(25)]` `:. V=(mz^(2)e^(4))/(8 epsilon_(0)^(2)h^(3))[(9)/(16xx25)] " " ...(1)` and frequency `v_(4)=(1)/(T)=(v)/(2pir)=((ZE^(2))/(2 epsilon_(0)nh))(1)/(2pi)((pi m z e^(2))/(epsilon_(0)h^(2)n^(2)))=(z^(2)e^(4)m)/(4 epsilon_(0)^(2)n^(3)h^(3)) "" ....(2)` `:. v//v_(4)=18//25` |
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