1.

A bolt having a diameter of 5 mm is loaded so that the shear stress in it is 120 MPa. Determine the value of the shear force on the bolt.

Answer»

Stress \(\sigma\) = \(\cfrac{forcce F}{area A}\) = hence, force = stress x area = stress \(\pi\)r2

= 120 x 106\(\pi\) \(\left(\cfrac{5\times10^{-3}}{2}\right)^2\)

= 2356 N or 2.356 kN



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