A bomb is dropped from an aeroplanewhen it is directly above a target at an height of 1000m .The aeroplane is moving horizontally with a speed of 500 kmh^(-1). By how much distance will the bomb miss the target ?

A bomb is dropped from an aeroplanewhen it is directly above a target

1.	A bomb is dropped from an aeroplanewhen it is directly above a target at an height of 1000m .The aeroplane is moving horizontally with a speed of 500 kmh^(-1). By how much distance will the bomb miss the target ?
Answer» Solution :As the aeroplane ismoving horizontally , the initial DOWNWARD VELOCITY of the bomb , `u_(y) = 0` Also, y = 1000 m `g = 9 . 8 ms^(-2) , t = ?` `:. 1000 = 0 + (1)/(2) xx 9 . 8t^(2)` ` = 4 . 9 t^(2)` (or)`t = sqrt((1000)/(4 . 9)) = (100)/(7) s` `{:("Horizontal"),("velocity of the"),("aeroplane"):}} = 500 kmh^(-1)` `= 500 xx (5)/(18) ms^(-1)` `= (1250)/(9) ms^(-1)` `{:("DISTANCE by"),("Which the bomb"),("misses the target"):}} = {{:("Horizontal distance covered"),("by the bomb before it"),("hits the ground"):}` = Horizontal velocity `xx`time `= (1250)/(9) xx (100)/(7) = 1984. 13 m `