1.

A bomb is rest at the summit of a cliff breaks into two equal fragments.One of the fragments attains a horizontal velocity of `20sqrt3 ms^(-1)`.The horizontal distance between the two fragments, when their displacement vectors is inclined at `60^(@)` relative to each other is `(g=10ms^(-2))`A. `40sqrt3`B. `80sqrt3`C. `120sqrt3`D. `480sqrt3`

Answer» Correct Answer - D
`x=(u_(1)u_(2))(2sqrt(u_(1)u_(2)))/g "cot" theta/2`


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