A bomb of 1 kg is thrown vertically up with speed 100 m/s. After 5 seconds, it explodes into two parts. One of mass 400 gm goes down with speed 25 m/s. What will happen to the other part just afterexplosion.

A bomb of 1 kg is thrown vertically up with speed 100 m/s. After 5 sec

1.	A bomb of 1 kg is thrown vertically up with speed 100 m/s. After 5 seconds, it explodes into two parts. One of mass 400 gm goes down with speed 25 m/s. What will happen to the other part just afterexplosion.
Answer» <html><body><p></p>Solution :After 5 sec, velocity of bomb<br/><a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a> = u - gt `= 100-10xx5=50 m//s`<br/>`therefore` initial momentum before explosion<br/>`= 1xx50 <a href="https://interviewquestions.tuteehub.com/tag/kg-1063886" style="font-weight:bold;" target="_blank" title="Click to know more about KG">KG</a> ms^(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)`<br/>From momentum conservation,<br/>`1xx50=-0.4xx25+0.6 v.`<br/>`therefore v.=100 m//s`, upwards.</body></html>