A bomb of 10 kg at rest explodes into two pieces of mass 4 kg and 6 kg. If the velocity of 4 kg mass is 6 ms^(-1)then the velocity of 6 kg is

A bomb of 10 kg at rest explodes into two pieces of mass 4 kg and 6 kg

1.	A bomb of 10 kg at rest explodes into two pieces of mass 4 kg and 6 kg. If the velocity of 4 kg mass is 6 ms^(-1)then the velocity of 6 kg is
Answer» `4ms^(-1)` `6ms^(-1)` `24 ms^(-1) ` `2.2 ms^(-1)` Solution :ACCORDING to LAW of consevation of momentum `m_1v_1+ m_2 v_2 = 0` ` v_2 = (m_1v_1)/(m_2) = - (4 xx 6)/(6 ) = - 4ms^(-1)`