A bomb of `1kg` is thrown vertically up with speed `100m//s` After 5 seconds it explodes into two parts. One part of mass `400gm` goes down with speed `25m//s` What will happen to the other part just after explosion .A. `100 ms^(-1)` upwardB. `600 ms^(-1)` upwardC. `100 ms^(-1)` downwardD. `300 ms^(-1)` upward

A bomb of `1kg` is thrown vertically up with speed `100m//s` After 5 s

1.	A bomb of `1kg` is thrown vertically up with speed `100m//s` After 5 seconds it explodes into two parts. One part of mass `400gm` goes down with speed `25m//s` What will happen to the other part just after explosion .A. `100 ms^(-1)` upwardB. `600 ms^(-1)` upwardC. `100 ms^(-1)` downwardD. `300 ms^(-1)` upward
Answer» Correct Answer - A Velocity of particle after 5s `v = u-gt=100-10xx5` `=100-50=50ms^(-1)` (upwards) Conservation of linear momentum gives `Mv = m_(1)v_(1) + m_(2)v_(2)`................(i) Taking upward direction positive, `v_(1) = -25 ms^(-1), v=50ms^(-1)` `M=1kg, m_(1) = 400g = 0.4Kg` `m_(2) = M-m_(1) = 1-0.4=0.6kg` From eq (i), `1 xx 50=0.4xx(-25)+0.6v_(2)` or `v_(2) = 100 ms^(-1)` (upwards)`

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