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A bomb of mass 6 kg initially at rest explodes in to three identical fragments. One of the fragments moves with a velocity of10sqrt(3)hatim//s , another fragment moves with a velocity of 10hatjm//s, then the third fragment moves with a velocity of magnitude. |
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Answer» Solution :`P_(3)=-(P_(1)+P_(2)), P_(3)=SQRT(P_(1)^(2)+P_(2)^(2))`, `m_(3)v_(3)=sqrt((m_(1)v_(1))^(2)+(m_(2)v^(2))^(2))` |
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