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A bomb of mass 9 kg explodes into two pieces of masses 3 kg and 6 kg. The velocity of mass 3 kg is 16 m s^(-1). The kinetic energy of mass 6 kg in joule is |
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Answer» 96 `0 = m_1 v_1+ m_2v_2 " or " m_2v_2 = -m_1v_1` Taking only the magnitude, `m_2v_2 = m_1v_1` `:. K_2 = 1/2 m_2v_2^2 = 1/2 (m_2^2 v_2^2)/(m_2) = (m_1^2 v_1^2)/(2m_2) "(Using (i))"` `= ((3)^2 xx (16)^2)/(2 xx 6) = 192 J` |
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