InterviewSolution
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InterviewSolution
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(a) Bond angle in PH_4 is higher than that in PH_3. Why ? (b) What is formed when PH_3 reacts with an acid ? |
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Answer» SOLUTION :(a) In `PH_3`, the presence of lone pair caused the l.p-b.p repulsions which results in decrease of bond angle where as in `PH_4^(+)` there are no I.p. of electrons and so MOLECULE experience only b.p-b.p repulsions. As Ip-b.p. repulsions are greater than b.p.-b.p. repulsions bond angle in `PH_(4)^(+)`is higher than `PH_(3)`. (b) With an acid, `PH_3` forms phosphonium SALT. For EXAMPLE, with HI, it forms phosphonium iodide `PH_(3) + HI to underset("Phosphonium iodide")(PH_(4)^(+))^(-)` |
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