1.

A bottel weighing 220 g and of area of cross-section 50 cm^(2), and height 4 cm oscillats on the surface of water in vertical position. Its frequency of oscillation is :

Answer»

`2.5 Hz`
`4.5 Hz`
`3.5 Hz`
`1.5 Hz`

Solution :Let H be the depth of BOTTLE in water tyhen
`A h rhog= mg`
(or) `h=(m)/(A RHO)`
Now time PERIOD,
`T=2pi sqrt((h)/(g))`
(or) `f=(1)/(T)=(1)/(2pi) sqrt((g)/(h))`
`=(7)/(2xx22) sqrt((980)/(4))`
`[ :. G=980 cm//s^(2), h= 4cm]`
`=2.5 Hz`


Discussion

No Comment Found