A box contains 5 red and 4 white marbles. Two marbles are drawn successively from the box without replacement and the second drawn marble drawn is found to be white. Probability that the first marble is also white is

A box contains 5 red and 4 white marbles. Two marbles are drawn succes

1.	A box contains 5 red and 4 white marbles. Two marbles are drawn successively from the box without replacement and the second drawn marble drawn is found to be white. Probability that the first marble is also white is
Answer» Let A be the event that first marble is white. let B be the event that second marble is white. Let C be the event that first marble is not white. Applying Bayes theorem `P(A/B)=(P(B/A)P(A))/(P(B/A)P(A)+P(B/C)P(C))` therefore,`P(A/B)= (4/9 xx 3/8)/((4/9 xx 3/8)+(5/9 xx 4/8))=12/32=3/8`

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A box contains 5 red and 4 white marbles. Two marbles are drawn successively from the box without replacement and the second drawn marble drawn is found to be white. Probability that the first marble is also white is

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