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A box is failing freely. Inside the box, a particle is projected with some velocity v with respect to the box at an angle `theta` as shown in the figure. A. The path of the particle with respect to an observer sitting in the box will be a straight line.B. The acceleration of particle with respect to the box is zero.C. The path of the particle with respect to an observer sitting in the box will be a parabolaD. The acceleration of particle with respect to ground is g downward |
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Answer» Correct Answer - A::B::C Loss in KE = `(1)/(2) (m_(1)m_(2))/(m_(1)+m_(2))(V_("rel"))^(2)(1-e^(2))` |
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